=(2m)
(c
? a
) + c
[b
? (2m)
] = (c ? a)(c++a)
(2m)
+ (b ? 2m)(b++2m)
c
= (c ? a)[(c++a)
(2m)
+ (b++2m)
c
] And from here it is already become clear how the number (c ? a) is take out of brackets. Similarly, you can take out of brackets the factor a + b = c + 2m. But this is possible only for odd powers n. In this case, equation (10) will have the form A
B
C
D
= (2m)
, where A
= c – b = a ? 2m; B
= c – a = b ? 2m; C
= a + b = c + 2m; D
– polynomial of power n ? 3 [30].]
Then we obtain:
A
B
E
=(2m)
(10)
where A
= c?b=a?2m; B
=c?a=b?2m; E
– polynomial of power n?2.
Equation (10) is a ghost that can be seen clearly only on the assumption that the number {a
+b
?c
} is reduced when (1) is substituted into (8). But if it is touched at least once, it immediately crumbles to dust. For example, if A
?B
?E
=2m
?2
m
then as one of the options could be such a system:
A
B
=2m
E
=2
m