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All sciences. №7, 2023. International Scientific Journal

Год написания книги
2023
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Then the cycle repeats, but now the total energy of the electron and proton will not be 134.271 eV, but 134.345 eV and this energy remains completely stable. If we return to neutrinos, then their energy will be artificially derived from the reaction associated with the collision of an antineutrino and a proton, with the release of a neutron and a positron, which immediately annihilates. Now we should turn to a more industrial and realistic scale, explaining the real benefits of having such a system.

The first question is to initially generate and find these neutrons, namely to generate them artificially, that is, to direct the flow of protons and electrons with the right energy opposite each other. But at the same time, do not forget that both beams must have a strong focus, because if the beams disperse, there will simply be no collisions. Now, with regard to the energy given, it is clear that it does not matter in principle, because it is easy to add to all other values, so for example, you can choose an energy of 100 keV for electrons and 50 keV for protons – immediately ionizing them from hydrogen.

It turns out that protons are targets, and electrons are projectiles, as a result, 150 keV is added and neutrons are obtained, but before that, the electron energy is slowed down by an additional electromagnetic field created outside the accelerator chamber and drooping inside the compartment, where the reaction takes place. Thus, this energy for the proton is also reduced to values of the order of 1 keV, with the help of magnetic traps, so that they collide, and to eliminate the error by which the electron will simply rotate around the proton due to this additional kinetic energy, because, for comparison, the energy of the electron in the first orbit is 13.6 eV.

For both cases, about 10 MW of energy was expended, and therefore the beam currents are 100 A for electrons and 200 A for protons. This accelerator is a cyclotron, which is pulsed, so its frequency has an order of 12.19—12.2 MHz, with a beam charge of 8.2 MCL for electrons and 16.4 for protons, respectively. That is, about 5,0225 * 10

 neutrons are obtained in one act, and 6,125 * 10

 neutrons per second, and if we take into account that the half-life of a neutron is 611 seconds, then this part will halve after this time, and in a second the same lump of neutrons will be generated from each act per second. the same electrons, protons and electron antineutrinos.

Now, returning to the antineutrino, when neutrons are already available, it is important to describe the following system. There is a secondary chamber around the neutron chamber, in which protons with low energies of the order of 10—20 eV will have to rotate, but with as huge currents as possible. It is desirable to bring the currents in this case up to 4—5 MA, or to make several channels of rotation in a magnetic field, with such currents, maximizing the density of the location of protons around the chamber itself. Further, this whole system is placed in a huge tank with cadmium chloride, with a total volume of about 1000—1500 liters. The electron antineutrino, according to the method of Cowens and Reines, as in the experiment of 1956, will fly out to collide with protons located as tightly as possible. In the very experiment of the discoverers of neutrinos, they encountered hydrogen atoms in water, where the distance between two hydrogen atoms of two molecules was about 0.15 nm and was only 3 acts per hour. Here the distance is almost the Coulomb barrier of a proton or 1.4 fm, which is 10

 times more.

But here there is an action of one trick, in the last experiment about 200 liters of water or 6.69 * 10

 protons were used, but at the same time they had a huge distance between each other, but if the neutron chamber itself has a diameter of about 10 meters, then the circumference on the axis of rotation of the protons will be 34.54 meters with a sphere area of 1519.76 m

. And with a proton diameter of 10

 m and an area of 1.256 * 10

 m

, you need 1.21* 10

 protons for one proton «sphere», and for 5 «spheres» – 6.05* 10

 particles, but at 55 channels with a current of 500 MA or at a power of 5 GWh, 6.1875* 10

 protons have already been obtained, which ensures 100% capture of anti-neutrinos, while the introduced 5 GWh due to the efficiency of the circulation unit of 97—98% will be preserved and absorb only 100 MWh of energy, when generated with the number of anti-neutrinos equal to the number of neutrons in 610 seconds or 1.868125*10

 neutrons, with a half-life, with an energy of 0.246541 MeV each, additional neutrons are obtained when bombarded with protons, for 50 microseconds absorbed by cadmium chloride with the release of gamma quanta with an energy of 6—7 MeV and additionally a positron is released, which gives 2 more gamma quanta during annihilation with the first electron, 0.551 MeV, plus the initial energy of the antineutrino, so the total is 8.348541 MeV of energy.

Gamma quanta themselves perfectly capture advanced scintillation counters, generating energy of the order of 2.4953789 *10

 J from them in 610 seconds, which is equivalent to 69.316 TWh, only for antineutrinos, this energy will grow over time and become stable after 3 acts, equal to 0.246675704 MeV or equivalent to 69.3172 TWh.

But if we go back to protons and electrons, their energy will initially be 134.271 eV, until it increases to 134.345 and becomes stable. So you can increase energy, but if you pay attention, each time the increase is the same energy, therefore, so much should be taken out of the cycle. When the necessary neutrons were created in the accelerator and this whole system, where they are also divided into electrons and protons that are attracted to each other, already in the same chamber they are transferred to a small compartment – a kind of TOKAMAK with the help of electromagnets, which, although they consume a lot, but not a little energy is generated. So this plasma begins to rotate inside the torus, around which thousands of metal wires are wrapped, which receive energy from electromagnetic induction.

The effect of electromagnetic induction is already known, and since these charges with such energies will flow, the current will flow on the external circuit and acquire energy. So, extracting 134.345 eV each time, this system is maintained in a stable state, now you can turn off the accelerator – it will no longer be useful, only if there is no need to increase the number of particles.

As a result, having spent only 6 GWh in total to create beams, shells of protons and others, as well as about a part on the accelerator and magnets, that is, in total about 7—8 GWh of energy, it turns out with the number of neutrons in 3,73625* 10

 particles and from each 134.345 eV or 1,115 GW *h on electrons-protons and 246.676 keV or 69.3172 TW * h on antineutrinos, it turns out – as much as 69.3183 TW * h, this is almost 8,665 times more! For comparison, resonant nuclear reactions, with all due respect to them as their discoverer, increase only 17.5 times.

It turns out that the force of attraction by a charge is used here and energy is obtained from this, because these forces and laws will always act and will not change their strength! It turns out that the force of attraction by the charge is used here and electrical energy is derived from this, because these forces and laws will always act and will not change their strength. Moreover, the system is fully controlled, the only thing is, if you increase the number of neutrons and wait for the right stage, you can artificially produce one of the most powerful explosions.

With this technology, it is possible to supply a maximum current of up to 12.2 MA for neutrons for high-current devices, and if the energy of the tsar bomb or AN-602 leaves 2.4* 10

 J, for resonant nuclear reactions at such a current, 2.554* 10

 J of energy is released, or 10.64 times more, and for one neutron unit at the same time at the same current, 3,04446 * 10

 J is released, that is, it can generate such a volume of energy that in its power will exceed the strongest instantaneous uranium energy release from the tsar bomb, with this calculation by 126 852.5 times.

Used literature

1. Brown, A. G. Atomic and nuclear physics. Elements of quantum mechanics. Workshop: Textbook / A. G. Brown, I. G. Levitina. – M.: Infra-M, 2019. – 352 p.

2. Deltsov, V. P. Physics: to get to the very essence! Desktop book for in—depth study of physics in secondary school: Atomic and nuclear physics / V. P. Deltsov, V. V. Deltsov. – M.: Lenand, 2017. – 176 p.

3. Kalashnikov, N. P. Practicum on solving problems in the general course of physics. Fundamentals of quantum physics. The structure of matter. Atomic and nuclear physics: A textbook / N. P. Kalashnikov. – St. Petersburg: Lan, 2014. – 240 p.

4. Lange, V. N. Physical paradoxes, sophisms and entertaining tasks. Book 2: Electricity and Magnetism. Vibrations and waves. Optics. The theory of relativity. Atomic and nuclear physics / V. N. Lange. – M.: CD Librocom, 2018. – 232 p.

5. Landsberg, G. S. Elementary textbook of physics of Vibrations and waves, optics, atom. and nuclear physics vol.3 / G. S. Landsberg. – M.: Fizmatlit, 2012. – 664 p.

6. Landsberg, G. S. Elementary textbook of Physics vol.3 Vibrations and waves, optics, atomic and nuclear physics. 15th i / G. S. Landsberg. – M.: Fizmatlit, 2016. – 664 p.

7. Landsberg, G. S. Elementary textbook of Physics. Vol.3. Wave oscillations. Optics. Atomic and nuclear physics: Textbook / G. S. Landsberg. – M.: Fizmatlit, 2016. – 664 p.

8. Mukhin, K. N. Experimental nuclear physics. Vol. 1. Physics of the atomic nucleus: Textbook / K. N. Mukhin. – SPb.: Lan, 2009. – 384 p.

9. Mukhin, K. N. Experimental nuclear Physics. Vol. 1. Physics of the atomic nucleus: Textbook / K. N. Mukhin. – St. Petersburg: Lan, 2008. – 384 p.

10. Mukhin, K. N. Experimental nuclear physics. Vol. 2. Physics of nuclear reactions: Textbook / K. N. Mukhin. – St. Petersburg: Lan, 2009. – 326 p.

11. Mukhin, K. N. Experimental nuclear physics. Vol. 2. Physics of nuclear reactions: Textbook / K. N. Mukhin. – St. Petersburg: Lan, 2008. – 336 p.

12. Rakobolskaya, I. V. Nuclear physics / I. V. Rakobolskaya. – M.: Krasand, 2014. – 248 p.

13. Sivukhin, D. V. General course of physics Vol.5. Atomic and nuclear physics: Textbook / D. V. Sivukhin. – M.: Fizmatlit, 2008. – 784 p.

14. Sivukhin, D. V. General course of physics Vol.5 Atomic and nuclear physics: Textbook 5 vol. / D. V. Sivukhin. – M.: Fizmatlit, 2008. – 784 p.

15. Sivukhin, D. V. General course of physics Volume 5 Atomic and nuclear physics: Textbook / D. V. Sivukhin. – M.: Fizmatlit, 2008. – 784 p.

16. Sivukhin, D. V. General course of physics. In 5 vols. 5. Atomic and nuclear physics, ster / D. V. Sivukhin. – M.: Fizmatlit, 2008. – 784 p.

17. Sivukhin, D. V. General course of physics. 5. Atomic and nuclear physics: A textbook for universities / D. V. Sivukhin. – M.: FIZMATLIT, 2008. – 784 p.

18. Sivukhin, D. V. General course of physics: Textbook: for universities in 5 volumes. Volume 5. Atomic and nuclear physics / D. V. Sivukhin. – M.: Fizmatlit, 2008. – 784 p.

19. Strelkov, S. P. Workshop on solving problems in the general course of physics. Fundamentals of quantum physics. The structure of matter. Atomic and nuclear physics: Textbook / S. P. Strelkov, D. V. Sivukhin, V. A. Ugarov. – St. Petersburg: Lan, 2014. – 240 p.

20. Tarasov, L. M. Experimental nuclear physics. Vol. 2. Physics of nuclear reactions: Textbook / L. M. Tarasov, I. G. Konstantinova. – SPb.: Lan P, 2016. – 326 p.
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